The electrolytic cells,one containing acidifi | vedclass

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(D) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes connected in seri

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$3 : 2$

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(D) According to Faraday's second law of electrolysis,when the same quantity of electricity is passed through different electrolytes connected in series,the mass of substances deposited is proportional to their equivalent weights. For $Fe^{2+} 	o Fe$,the change in oxidation state is $2$,so the equivalent weight is $E_1 = \frac{	ext{Atomic weight}}{2}$. For $Fe^{3+} 	o Fe$,the change in oxidation state is $3$,so the equivalent weight is $E_2 = \frac{	ext{Atomic weight}}{3}$. The ratio of the mass of iron deposited is $W_1 : W_2 = E_1 : E_2 = \frac{	ext{Atomic weight}}{2} : \frac{	ext{Atomic weight}}{3} = 3 : 2$.

List $I$ (Conversion)	List $II$ (Number of Faraday required)
$A$. $1 \text{ mole of } H_2O \text{ to } O_2$	$I$. $3F$
$B$. $1 \text{ mol of } MnO_4^- \text{ to } Mn^{2+}$	$II$. $2F$
$C$. $1.5 \text{ mol of } Ca \text{ from molten } CaCl_2$	$III$. $1F$
$D$. $1 \text{ mol of } FeO \text{ to } Fe_2O_3$	$IV$. $5F$

The electrolytic cells,one containing acidified ferrous chloride and another acidified ferric chloride,are connected in series. The ratio of iron deposited at the cathodes in the two cells when electricity is passed through the cells will be:

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