The electron affinities of halogens are $F = 322, Cl = 349, Br = 324, I = 295 \ kJ \ mol^{-1}$. The higher value for $Cl$ as compared to that of $F$ is due to :-

  • A
    Weaker electron-electron repulsion in $Cl$
  • B
    Higher atomic radius of $F$
  • C
    Smaller electronegativity of $F$
  • D
    More vacant $p$-subshell in $Cl$

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Discuss the factors affecting electron gain enthalpy and the trend in its variation in the periodic table.

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Column-$I$ shows the electronic configuration of some elements and Column-$II$ shows the values of electron gain enthalpy. Match these values correctly. Match the electronic configuration with the electron gain enthalpy.
Column-$I$ Electronic Configuration Column-$II$ Electron Gain Enthalpy / $kJ \ mol^{-1}$
$(A) \ 1s^2 2s^2 2p^6$ $(1) -53$
$(B) \ 1s^2 2s^2 2p^6 3s^1$ $(2) -328$
$(C) \ 1s^2 2s^2 2p^5$ $(3) -141$
$(D) \ 1s^2 2s^2 2p^4$ $(4) +53$

The amount of energy released on the addition of an electron in the outermost shell of an atom is called:

Which of the following has the highest electron affinity $(EA)$?

The electron gain enthalpy $\Delta_{eg}H$ of $Cl_{(g)}$ is $-349 \ kJ \ mol^{-1}$. If the ground state energy of $Cl_{(g)}$ is $x \ kJ \ mol^{-1}$,the ground state energy (in $kJ \ mol^{-1}$) of $Cl^{-}_{(g)}$ is

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