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(B) The ground state corresponds to $n = 1$.The first excited state corresponds to $n = 2$.The second excited state corresponds to $n = 3$.When the el

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$3$

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(B) The ground state corresponds to $n = 1$.The first excited state corresponds to $n = 2$.The second excited state corresponds to $n = 3$.When the electron transitions from an initial state $n_i = 3$ to a final state $n_f = 1$, the number of possible spectral lines is given by the formula $N = \frac{n(n-1)}{2}$, where $n$ is the initial energy level.Alternatively, we can list the possible transitions: $1$. From $n = 3$ to $n = 2$$2$. From $n = 2$ to $n = 1$$3$. From $n = 3$ to $n = 1$Total number of spectral lines = $3$.

The electron in a hydrogen atom is initially in the second excited state. When it finally moves to the ground state, the maximum number of spectral lines emitted are:

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