The electronegativity of C,H,O,N and S are 2. | vedclass

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(A) The polarity of a bond depends on the difference in electronegativity between the two bonded atoms. The greater the difference,the more polar the

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$O-H$

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(A) The polarity of a bond depends on the difference in electronegativity between the two bonded atoms. The greater the difference,the more polar the bond.$1$. For $O-H$: $\Delta EN = |3.5 - 2.1| = 1.4$$2$. For $S-H$: $\Delta EN = |2.5 - 2.1| = 0.4$$3$. For $N-H$: $\Delta EN = |3.0 - 2.1| = 0.9$$4$. For $C-H$: $\Delta EN = |2.5 - 2.1| = 0.4$Since the electronegativity difference is highest for the $O-H$ bond,it is the most polar bond.

The electronegativity of $C$,$H$,$O$,$N$ and $S$ are $2.5$,$2.1$,$3.5$,$3.0$ and $2.5$ respectively. Which of the following bonds is most polar?

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