The electronic configuration of a metal ion in its complex is $[Ar] 3d^4$. For this metal complex,$\Delta_o < P$ ($P=$ energy required for electron pairing in a single orbital). The distribution of electrons in the complex is:
- A$(t_{2g})^3 (e_g)^1$
- B$(t_{2g})^2 (e_g)^2$
- C$(t_{2g})^4 (e_g)^0$
- D$(t_{2g})^1 (e_g)^3$
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Low spin complex of $d^6$ cation in an octahedral field will have the following energy:
($\Delta_o =$ crystal field splitting energy in an octahedral field,$P =$ Electron pairing energy)
($\Delta_o =$ crystal field splitting energy in an octahedral field,$P =$ Electron pairing energy)
MediumAIPMT 2012
View SolutionWhich of the following are true about the energy of the given d-orbitals of a tetrahedral complex?
$A$. $d_{xy} = d_{xz} > d_{x^2-y^2}$
$B$. $d_{xy} = d_{yz} > d_{z^2}$
$C$. $d_{x^2-y^2} > d_{z^2} > d_{xz}$
$D$. $d_{x^2-y^2} = d_{z^2}$
Choose the correct answer from the given below:
$A$. $d_{xy} = d_{xz} > d_{x^2-y^2}$
$B$. $d_{xy} = d_{yz} > d_{z^2}$
$C$. $d_{x^2-y^2} > d_{z^2} > d_{xz}$
$D$. $d_{x^2-y^2} = d_{z^2}$
Choose the correct answer from the given below:
Match List-$I$ with List-$II$.
List-$I$ (Coordination entity) List-$II$ (Wavelength of light absorbed in $nm$) $A$. $[CoCl(NH_3)_5]^{2+}$ $I$. $310$ $B$. $[Co(NH_3)_6]^{3+}$ $II$. $475$ $C$. $[Co(CN)_6]^{3-}$ $III$. $535$ $D$. $[Cu(H_2O)_4]^{2+}$ $IV$. $600$
Choose the correct answer from the options given below:
| List-$I$ (Coordination entity) | List-$II$ (Wavelength of light absorbed in $nm$) |
|---|---|
| $A$. $[CoCl(NH_3)_5]^{2+}$ | $I$. $310$ |
| $B$. $[Co(NH_3)_6]^{3+}$ | $II$. $475$ |
| $C$. $[Co(CN)_6]^{3-}$ | $III$. $535$ |
| $D$. $[Cu(H_2O)_4]^{2+}$ | $IV$. $600$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2023
View SolutionWhat is the electronic arrangement of a metal atom/ion in an octahedral complex with $d^4$ configuration,if $\Delta_0 < P$ (pairing energy)?
Medium
View SolutionThe increasing order of the crystal field splitting power of some common ligands is
Medium
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