Easy
The electronic configuration of cobalt ($Co$,atomic number $27$) is:
- A$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^1, 4s^2$
- B$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^7, 4s^2$
- C$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^3, 4s^2$
- D$1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^5, 4s^2$
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The maximum number of electrons in a $p$-orbital with $n=5, m=1$ is$-$
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Easy
View SolutionWrite the electronic configuration of the following ions:
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Easy
View SolutionThe total number of atomic orbitals in the fourth energy level of an atom is
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