Medium
The electronic configurations of four elements are given in brackets: $L\,(1s^2, 2s^2 2p^1)$; $M\,(1s^2, 2s^2 2p^5)$; $Q\,(1s^2, 2s^2 2p^6, 3s^1)$; $R\,(1s^2, 2s^2 2p^2)$. Which element would most readily form a diatomic molecule?
- A$Q$
- B$M$
- C$R$
- D$L$
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Similar Questions
For principal quantum number $n = 4$,the total number of orbitals having $l = 3$ is:
MediumAIIMS 2004
View SolutionFor the given quantum numbers,write the name of the subshell,the values of the magnetic quantum number $(m_l)$,and the number of orbitals:
$(i) \ n = 3, \ l = 2$
$(ii) \ n = 4, \ l = 3$
$(iii) \ n = 2, \ l = 0$
$(iv) \ n = 5, \ l = 1$
$(i) \ n = 3, \ l = 2$
$(ii) \ n = 4, \ l = 3$
$(iii) \ n = 2, \ l = 0$
$(iv) \ n = 5, \ l = 1$
Easy
View SolutionWhich of the following rules or principles states that "No two electrons in an atom can have the same set of four quantum numbers"?
The total number of atomic orbitals in the fourth energy level of an atom is
Which of the following configurations is correct for iron $(Fe)$?
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