The electronic spectrum of [Ti(H_2O)_6]^{3+} | vedclass

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Question

(B) The electronic transition in $[Ti(H_2O)_6]^{3+}$ corresponds to the excitation of the electron from the $t_{2g}$ orbital to the $e_g$ orbital,whic

Vedclass · Accepted Answer

$243$

Vedclass · Answer

(B) The electronic transition in $[Ti(H_2O)_6]^{3+}$ corresponds to the excitation of the electron from the $t_{2g}$ orbital to the $e_g$ orbital,which is equal to the crystal field splitting energy,$\Delta_0$.Given $\Delta_0 = 20300 \, cm^{-1}$.Using the conversion factor $1 \, kJ \, mol^{-1} = 83.7 \, cm^{-1}$:$\Delta_0 = \frac{20300 \, cm^{-1}}{83.7 \, cm^{-1} \, kJ^{-1} \, mol} \approx 242.53 \, kJ \, mol^{-1}$.Rounding to the nearest integer,we get $243 \, kJ \, mol^{-1}$.Thus,option $B$ is the correct answer.

The electronic spectrum of $[Ti(H_2O)_6]^{3+}$ gives a single broad peak with a maxima at $20300 \, cm^{-1}$. The crystal field stabilization energy is equal to .......... $kJ \, mol^{-1}$

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