The element with quantum numbers $n = 2, l = 1, m = 1, s = -1/2$ has the following position in the periodic table:

The maximum number of electrons in an atom with $l = 2$ and $n = 3$ is

The orbital occupied by an electron with quantum numbers $n = 4, l = 3, m = 0$ and $s = -\frac{1}{2}$ is called

The angular momentum of an electron in a $d$ orbital is equal to:

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination$(s)$ has/have the same energy,list them:
$(1).$ $n=4, l=2, m_l=-2, m_s=-1/2$
$(2).$ $n=3, l=2, m_l=1, m_s=+1/2$
$(3).$ $n=4, l=1, m_l=0, m_s=+1/2$
$(4).$ $n=3, l=2, m_l=-2, m_s=-1/2$
$(5).$ $n=3, l=1, m_l=-1, m_s=+1/2$
$(6).$ $n=4, l=1, m_l=0, m_s=+1/2$

Which orbital is dumb-bell shaped?