The empirical formula of a compound is $CH_2O$ and its molecular weight is $120$. The molecular formula of the compound is:

$A$ $64 \, g$ organic compound contains $24 \, g$ of carbon,$8 \, g$ of hydrogen,and the rest is oxygen. The empirical formula of this compound is .....

Number of $g$ of oxygen in $32.2\,g$ of $Na_2SO_4 \cdot 10H_2O$ is

$A$ hydrocarbon has $C = 85.72\%$ and the remaining is $H$. The hydrocarbon is:

In $CH_3CH_2Br$,the percentage of $Br$ is:

$A$ hydrocarbon contains $10.5 \, g$ of carbon and $1 \, g$ of hydrogen. If the volume of $2.4 \, g$ of this hydrocarbon is $1 \, L$ at $127 \, ^\circ C$ and $1 \, atm$ pressure,then the hydrocarbon is: