The end product (C) in the following sequence | vedclass

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(C) Step $1$: Hydration of ethyne $(HC \equiv CH)$ in the presence of $1\% \ HgSO_4$ and $20\% \ H_2SO_4$ (Kucherov reaction) yields acetaldehyde $(CH

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acetone

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(C) Step $1$: Hydration of ethyne $(HC \equiv CH)$ in the presence of $1\% \ HgSO_4$ and $20\% \ H_2SO_4$ (Kucherov reaction) yields acetaldehyde $(CH_3CHO)$ as product $A$.Step $2$: Reaction of acetaldehyde $(CH_3CHO)$ with methylmagnesium halide $(CH_3MgX)$ followed by hydrolysis $(H_2O)$ gives propan$-2-$ol $(CH_3CHOHCH_3)$ as product $B$.Step $3$: Oxidation $([O])$ of propan$-2-$ol $(CH_3CHOHCH_3)$ yields acetone $(CH_3COCH_3)$ as the final product $C$.

The end product $(C)$ in the following sequence of reactions is:
$HC \equiv CH$ $\xrightarrow[20\% \ H_2SO_4]{1\% \ HgSO_4} A$ $\xrightarrow[H_2O]{CH_3MgX} B$ $\xrightarrow{[O]} (C)$

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The end product $(C)$ in the following sequence of reactions is:$HC \equiv CH$ $\xrightarrow[20\% \ H_2SO_4]{1\% \ HgSO_4} A$ $\xrightarrow[H_2O]{CH_3MgX} B$ $\xrightarrow{[O]} (C)$