The end product in the reaction is:

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(B) The reaction sequence is as follows: $1$. The first step is the Reimer-Tiemann reaction,where phenol reacts with $CHCl_3$ and $OH^-$ to form $o$-h

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(B) The reaction sequence is as follows: $1$. The first step is the Reimer-Tiemann reaction,where phenol reacts with $CHCl_3$ and $OH^-$ to form $o$-hydroxybenzaldehyde (salicylaldehyde) as the intermediate product $X$. $2$. The second step involves the treatment of $o$-hydroxybenzaldehyde with $50\% \ NaOH$ (concentrated alkali),which leads to the Cannizzaro reaction. $3$. In the Cannizzaro reaction,the aldehyde group is disproportionated into an alcohol group $(-CH_2OH)$ and a carboxylate group $(-COO^-)$. $4$. Thus,the final products $Y$ and $Z$ are $2$-hydroxybenzyl alcohol and $2$-hydroxybenzoate ion,respectively.

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