The energy (in $eV$) associated with the electron in the $1^{st}$ orbit of $Li^{2+}$ is
- A$-122.4$
- B$-61.15$
- C$-30.5$
- D$-244.6$
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Medium
View SolutionThe radius of the second Bohr orbit,in terms of the Bohr radius,$a_{0}$,in $Li^{2+}$ is
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