The energy of a photon is 3 times 10^{-12} e | vedclass

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(A) Given:$E = 3 	imes 10^{-12} \ erg$$h = 6.62 	imes 10^{-27} \ erg \cdot s$$c = 3 	imes 10^{10} \ cm/s$Using the formula $E = \frac{hc}{\lambda}$

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(A) Given:$E = 3 	imes 10^{-12} \ erg$$h = 6.62 	imes 10^{-27} \ erg \cdot s$$c = 3 	imes 10^{10} \ cm/s$Using the formula $E = \frac{hc}{\lambda}$,we have:$\lambda = \frac{hc}{E}$$\lambda = \frac{6.62 	imes 10^{-27} 	imes 3 	imes 10^{10}}{3 	imes 10^{-12}} \ cm$$\lambda = 6.62 	imes 10^{-5} \ cm$Since $1 \ cm = 10^7 \ nm$,$\lambda = 6.62 	imes 10^{-5} 	imes 10^7 \ nm$$\lambda = 6.62 	imes 10^2 \ nm = 662 \ nm$.

The energy of a photon is $3 \times 10^{-12} \ erg$. What is its wavelength in $nm$?
$(h = 6.62 \times 10^{-27} \ erg \cdot s; c = 3 \times 10^{10} \ cm/s)$

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The energy of a photon is $3 \times 10^{-12} \ erg$. What is its wavelength in $nm$?$(h = 6.62 \times 10^{-27} \ erg \cdot s; c = 3 \times 10^{10} \ cm/s)$