The energy of an electron in a hydrogen atom | vedclass

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(C) The energy of an electron in a hydrogen atom is given by the formula: $E_n = \frac{-13.6 \ eV}{n^2}$.For $n=1$, $E_1 = \frac{-13.6}{1^2} = -13.6 \

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$36 : 9 : 4$

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(C) The energy of an electron in a hydrogen atom is given by the formula: $E_n = \frac{-13.6 \ eV}{n^2}$.For $n=1$, $E_1 = \frac{-13.6}{1^2} = -13.6 \ eV$.For $n=2$, $E_2 = \frac{-13.6}{2^2} = -3.4 \ eV$.For $n=3$, $E_3 = \frac{-13.6}{3^2} = -1.51 \ eV$.The ratio $E_1 : E_2 : E_3$ is $\frac{-13.6}{1} : \frac{-13.6}{4} : \frac{-13.6}{9}$.Dividing by $-13.6$, we get $1 : \frac{1}{4} : \frac{1}{9}$.Multiplying by $36$ to clear the denominators, we get $36 : 9 : 4$.

The energy of an electron in a hydrogen atom when present in $n=1$, $n=2$, and $n=3$ will be in the ratio of:

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