The energy of an electron in the 3^{rd} orbit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Bohr's theory,the energy of an electron in the $n^{th}$ orbit is given by $E_n = -\frac{Z^2 R_H}{n^2}$,which implies $E_n \propto \fr

Vedclass · Accepted Answer

$-9E$

Vedclass · Answer

(D) According to Bohr's theory,the energy of an electron in the $n^{th}$ orbit is given by $E_n = -\frac{Z^2 R_H}{n^2}$,which implies $E_n \propto \frac{1}{n^2}$.Given,the energy of the electron in the $3^{rd}$ orbit is $E_3 = -E$.Using the relation $E_n \propto \frac{1}{n^2}$,we have:$\frac{E_1}{E_3} = \frac{3^2}{1^2} = \frac{9}{1} = 9$.Therefore,$E_1 = 9 	imes E_3 = 9 	imes (-E) = -9E$.Thus,the energy in the first orbit is $-9E$,and option $(D)$ is correct.

The energy of an electron in the $3^{rd}$ orbit of a hydrogenic atom is $-E$. The energy of an electron in the first orbit will be

Similar Questions

An inverted bell lying at the bottom of a lake $47.6 \, m$ deep has $50 \, cm^3$ of air trapped in it. The bell is brought to the surface of the lake. The volume of the trapped air will be ......... $cm^3$ (atmospheric pressure $= 70 \, cm$ of $Hg$ and density of $Hg = 13.6 \, g/cm^3$).

If $0.5 \ mol$ of $CaBr_2$ is mixed with $0.2 \ mol$ of $K_3PO_4$,then the maximum number of moles of $Ca_3(PO_4)_2$ obtained will be:

Assertion : Cattle breeds can be improved by super ovulation and embryo transplantation.
Reason : Superovulation in high milk-yielding cows is induced by hormonal injection.

The major product in the following reaction is:

The oxoacid of sulphur which contains two sulphur atoms in different oxidation states is

Vedclass Test Series

Exam Paper Generator

Online Exam Module