The energy of the electron at infinite distan | vedclass

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Question

(A) In the Bohr model,the energy of an electron in the $n^{th}$ orbit is given by the expression $E_{n} = -13.6 	imes \frac{Z^{2}}{n^{2}} 	ext{ eV}$

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Zero

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(A) In the Bohr model,the energy of an electron in the $n^{th}$ orbit is given by the expression $E_{n} = -13.6 	imes \frac{Z^{2}}{n^{2}} 	ext{ eV}$.As the distance from the nucleus increases,the value of $n$ increases.When the electron is at an infinite distance from the nucleus,$n = \infty$.Substituting $n = \infty$ into the formula,we get $E_{\infty} = -13.6 	imes \frac{Z^{2}}{\infty^{2}} = 0$.Therefore,the energy of the electron at infinite distance from the nucleus is taken as zero.

The energy of the electron at infinite distance from the nucleus in Bohr’s model is taken as:

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