The energy released if hydrogen atoms are com | vedclass

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Question

(B) The nuclear fusion reaction is: $2 	imes ^{2}_{1}H 	o ^{4}_{2}He$.
Binding energy of one $^{2}_{1}H$ nucleus $= 2 	imes 1.1 	ext{ MeV} = 2.2

Vedclass · Accepted Answer

$24.4$

Vedclass · Answer

(B) The nuclear fusion reaction is: $2 	imes ^{2}_{1}H 	o ^{4}_{2}He$.
Binding energy of one $^{2}_{1}H$ nucleus $= 2 	imes 1.1 	ext{ MeV} = 2.2 	ext{ MeV}$.
Total binding energy of reactants $= 2 	imes 2.2 	ext{ MeV} = 4.4 	ext{ MeV}$.
Binding energy of one $^{4}_{2}He$ nucleus $= 4 	imes 7.2 	ext{ MeV} = 28.8 	ext{ MeV}$.
Energy released $= 	ext{Binding energy of product} - 	ext{Binding energy of reactants}$.
Energy released $= 28.8 	ext{ MeV} - 4.4 	ext{ MeV} = 24.4 	ext{ MeV}$.

The energy released if hydrogen atoms are combined to form $^{4}_{2}He$ is . . . . . . MeV. (Take binding energies per nucleon of $^{2}H$ and $^{4}_{2}He$ as $1.1$ MeV and $7.2$ MeV, respectively)

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