The enthalpy of formation of $NH_3$ is $-46 \ kJ \ mol^{-1}$. The enthalpy change for the reaction $2 NH_{3(g)} \longrightarrow N_{2(g)} + 3 H_{2(g)}$ is

  • A
    $+184 \ kJ$
  • B
    $+23 \ kJ$
  • C
    $+92 \ kJ$
  • D
    $+46 \ kJ$

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Similar Questions

If $C_{(s)} + O_{2(g)} \rightarrow CO_{2(g)}$,$\Delta H = -X$,and $CO_{(g)} + \frac{1}{2} O_{2(g)} \rightarrow CO_{2(g)}$,$\Delta H = -Y$,calculate $\Delta_f H$ for $CO_{(g)}$ formation.

$S_{\text{(rhombic)}} + O_{2(g)} \rightarrow SO_{2(g)}; \Delta H = -297.5 \, kJ$
$S_{\text{(monoclinic)}} + O_{2(g)} \rightarrow SO_{2(g)}; \Delta H = -300 \, kJ$
From the given data,which of the following statements is correct?

Standard molar enthalpy of formation,$\Delta _{f}H^{o}$ is just a special case of enthalpy of reaction,$\Delta _{r}H^{o}$. Is the $\Delta _{r}H^{o}$ for the following reaction same as $\Delta _{f}H^{o}$? Give reason for your answer. $CaO_{(s)} + CO_{2_{(g)}} \to CaCO_{3_{(s)}}$; $\Delta _{r}H^{o} = -178.3 \ kJ \ mol^{-1}$

Average $C-H$ bond energy is $416 \ kJ \ mol^{-1}$. Which of the following is correct?

$S_{(g)} + \frac{3}{2} O_{2(g)} \rightarrow SO_{3(g)} + 2x \ kcal$
$SO_{2(g)} + \frac{1}{2} O_{2(g)} \rightarrow SO_{3(g)} + y \ kcal$
The heat of formation of $SO_{2(g)}$ is given by :

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