The equation of a circle is given by $x^2+y^2=a^2$,where $a$ is the radius. If the equation is modified to change the origin to a point other than $(0,0)$,find the correct dimensions of $A$ and $B$ in the new equation: $(x-At)^2+(y-\frac{t}{B})^2=a^2$. The dimensions of $t$ are given as $[T^{-1}]$.

  • A
    $A=[L^{-1}T], B=[LT^{-1}]$
  • B
    $A=[LT], B=[L^{-1}T^{-1}]$
  • C
    $A=[L^{-1}T^{-1}], B=[LT^{-1}]$
  • D
    $A=[L^{-1}T^{-1}], B=[LT]$

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