The equation of a line,whose perpendicular distance from the origin is $5$ units and the angle,which the perpendicular to the line from the origin makes,is $210^{\circ}$ with the positive $X$-axis,is

  • A
    $-x \sqrt{3}+y+10=0$
  • B
    $x \sqrt{3}+y-10=0$
  • C
    $x \sqrt{3}+y+10=0$
  • D
    $x \sqrt{3}-y+10=0$

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Similar Questions

Match the items given in List-$I$ to the items given in List-$II$.
List-$I$List-$II$
$A$. Line passing through $(-4, 3)$ and having intercepts in the ratio $5:3$$1$. $2x - 5y + 4 = 0$
$B$. Line passing through $P(2, -5)$ such that $P$ bisects the part intercepted between the axes$2$. $3x + 5y = 3$
$C$. Line parallel to $2x - 3y + 5 = 0$ with $x$-intercept $\frac{2}{5}$ is$3$. $10x - 15y + 4 = 0$
$D$. Line perpendicular to $5x + 2y + 7 = 0$ with $y$-intercept $\frac{4}{5}$ is$4$. $10x - 15y = 4$
$5$. $5x - 2y - 20 = 0$

If the length of the intercept made on the line $y=ax$ by the lines $y=2$ and $y=6$ is less than $5$,then which of the following is true?

Find the equation of the line passing through the point $(-2, 3)$ with a slope of $-4$.

Find the slope of the line passing through the points $(3, -2)$ and $(3, 4)$.

If the point $(3, -4)$ divides the segment of the line between the $X$-axis and $Y$-axis in the ratio $2 : 3$,then the equation of the line is:

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