The equation of a transverse wave is given by $y = 10\sin \pi (0.01x - 2t)$ where $x$ and $y$ are in $cm$ and $t$ is in seconds. Its frequency is .... $sec^{-1}$.

If the equation of a transverse wave is $y = 5\sin 2\pi \left[ \frac{t}{0.04} - \frac{x}{40} \right]$,where distance is in $cm$ and time is in seconds,then the wavelength of the wave is .... $cm$.

The path difference between two waves given by the equations $y_1 = a_1 \sin \left(\omega t - \frac{2 \pi x}{\lambda}\right)$ and $y_2 = a_2 \sin \left(\omega t - \frac{2 \pi x}{\lambda} + \phi\right)$ is

The figure shows the wave $y = A \sin(\omega t - kx)$. What is the magnitude of the slope of the curve at $B$?

The velocity of sound waves in air is $330 \; m/s$. For a particular sound wave in air,a path difference of $40 \; cm$ is equivalent to a phase difference of $1.6 \pi$. The frequency of this wave is ... $Hz$.

The equation of a wave motion (with $t$ in seconds and $x$ in metres) is given by $y = 7\sin(7\pi t - 0.4\pi x + \frac{\pi}{3})$. The velocity of the wave will be