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(A) The standard equation of a transverse wave is given by $y = A \sin(kz - \omega t)$.Comparing the given equation $y = 100 \sin \pi (0.04z - 2t)$ wi

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(A) The standard equation of a transverse wave is given by $y = A \sin(kz - \omega t)$.Comparing the given equation $y = 100 \sin \pi (0.04z - 2t)$ with the standard form,we distribute $\pi$ inside the parentheses:$y = 100 \sin (0.04\pi z - 2\pi t)$.Here,the angular frequency $\omega$ is the coefficient of $t$,which is $\omega = 2\pi 	ext{ rad/s}$.The relationship between angular frequency $\omega$ and frequency $f$ is $\omega = 2\pi f$.Substituting the value of $\omega$:$2\pi = 2\pi f$.Therefore,$f = 1 	ext{ Hz}$.

The equation of a transverse wave is given by $y = 100 \sin \pi (0.04z - 2t)$,where $y$ and $z$ are in $cm$ and $t$ is in seconds. The frequency of the wave in $Hz$ is

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