The equation of a wave is y = 2 sin pi (0.5x | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The standard equation of a progressive wave is given by $y = A \sin(kx - \omega t)$.Comparing the given equation $y = 2 \sin \pi (0.5x - 200t)$ wi

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(D) The standard equation of a progressive wave is given by $y = A \sin(kx - \omega t)$.Comparing the given equation $y = 2 \sin \pi (0.5x - 200t)$ with the standard form,we get:$y = 2 \sin (0.5\pi x - 200\pi t)$.Here,the wave number $k = 0.5\pi$ and the angular frequency $\omega = 200\pi$.The wave velocity $v$ is given by the ratio of the coefficient of $t$ to the coefficient of $x$:$v = \frac{\omega}{k} = \frac{200\pi}{0.5\pi} = 400 \ cm/sec$.

The equation of a wave is $y = 2 \sin \pi (0.5x - 200t)$,where $x$ and $y$ are expressed in $cm$ and $t$ in $sec$. The wave velocity is ...... $cm/sec$.

Similar Questions

In a plane progressive harmonic wave,the particle speed is always less than the wave speed if:

For a wave equation $Y = Y_0 \sin 2\pi \left( ft - \frac{x}{\lambda} \right) \text{ cm}$,the condition for the maximum particle velocity to be four times the wave velocity is:

Which of the following equations represents a travelling wave?

The equation of a longitudinal wave is represented as $y = 20 \cos \pi (50t - x)$. Its wavelength is ..... $cm$.

For a wave equation $y = 10 \sin \pi (0.01x - 2.00t) \text{ cm}$,what is the maximum particle velocity in $\text{cm/sec}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module