The equation of a wave is given by (all quant | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The standard wave equation is given by $Y = A \sin(\omega t - kx)$.Comparing this with the given equation $Y = 5 \sin(10\pi t - 0.1\pi x)$,we get

Vedclass · Accepted Answer

$\pi$

Vedclass · Answer

(B) The standard wave equation is given by $Y = A \sin(\omega t - kx)$.Comparing this with the given equation $Y = 5 \sin(10\pi t - 0.1\pi x)$,we get the wave number $k = 0.1\pi \ rad/m$.The phase difference $\Delta\phi$ between two points separated by a distance $\Delta x$ is given by the formula $\Delta\phi = k \cdot \Delta x$.Given $\Delta x = 10 \ m$ and $k = 0.1\pi \ rad/m$,we have:$\Delta\phi = (0.1\pi) 	imes 10 = \pi \ rad$.Therefore,the phase difference is $\pi$.

The equation of a wave is given by (all quantities expressed in $M.K.S.$ units) $Y = 5 \sin(10\pi t - 0.1\pi x)$ along the $x$-axis. The phase difference between two points separated by a distance of $10 \ m$ along the $x$-axis is:

Similar Questions

$A$ sound wave of frequency $500 \text{ Hz}$ travels between two points $X$ and $Y$ separated by a distance of $600 \text{ m}$ in a time of $2 \text{ s}$. The number of waves between the points $X$ and $Y$ are

The equation of a wave travelling along the positive $x$-axis,as shown in the figure at $t = 0$,is given by:

Write the definition,unit,and dimensional formula of amplitude.

The maximum particle velocity in a wave motion is half the wave velocity. Then the amplitude of the wave is equal to

The equation of a wave is given as $y = 0.07 \sin (12\pi x - 3000\pi t)$. Where $x$ is in $m$ and $t$ is in $s$,then the correct statement is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module