The equation of the parabola with vertex at $(0,0)$ and length of latus rectum equal to $\frac{16}{3}$ is:
- A$8x^{2} + 3y^{2} = 72$
- B$16y^{2} = 3x$
- C$3y^{2} = 16x$
- D$3x^{2} + 16y^{2} = 48$
Explore More
Similar Questions
The equation of the directrix of the parabola $x^2+8x+12y+4=0$ is
The axis of the parabola $x^{2}+2 x y+y^{2}-5 x+5 y-5=0$ is
DifficultWBJEE 2017
View SolutionThe equation of the line touching both parabolas $y^2=4x$ and $x^2=-32y$ is
The length of the latus rectum of the parabola $20(x^2+y^2-6x-2y+10) = (4x-2y-5)^2$ is
The smallest value of $x^2 - 3x + 3$ in the interval $(-3, 3/2)$ is
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo