The equilibrium constant at 298 K for the re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction is $A + B \rightleftharpoons C + D$. Initial concentrations: $[A] = 1 \ M, [B] = 1 \ M, [C] = 1 \ M, [D] = 1 \ M$. At equilibrium,let

Vedclass · Accepted Answer

$1.818$

Vedclass · Answer

(B) The reaction is $A + B \rightleftharpoons C + D$. Initial concentrations: $[A] = 1 \ M, [B] = 1 \ M, [C] = 1 \ M, [D] = 1 \ M$. At equilibrium,let the change in concentration be $x$. Equilibrium concentrations: $[A] = 1-x, [B] = 1-x, [C] = 1+x, [D] = 1+x$. The equilibrium constant expression is $K_c = \frac{[C][D]}{[A][B]}$. Given $K_c = 100$,we have: $100 = \frac{(1+x)(1+x)}{(1-x)(1-x)}$ Taking the square root on both sides: $10 = \frac{1+x}{1-x}$ $10(1-x) = 1+x$ $10 - 10x = 1 + x$ $9 = 11x$ $x = \frac{9}{11} \approx 0.818 \ M$. The equilibrium concentration of $D$ is $[D] = 1 + x = 1 + 0.818 = 1.818 \ M$.

The equilibrium constant at $298 \ K$ for the reaction $A + B \rightleftharpoons C + D$ is $100$. If the initial concentrations of all the four species were $1 \ M$ each,then the equilibrium concentration of $D$ (in $mol \ L^{-1}$) will be

Similar Questions

According to molecular orbital theory,the total number of bonding electron pairs in $O_2$ is

The half-life period of a first-order chemical reaction is $6.93 \, \text{min}$. The time required for the completion of $99 \%$ of the chemical reaction will be .......... $\text{min}$ $(\log \, 2 = 0.301)$.

$A$ graph of magnetic flux $\phi$ versus current $(I)$ is shown for four inductors $A, B, C, D$. The inductor with the smallest value of self-inductance is:

Which of the following statements is correct for diamagnetic materials?

Which of the following is the correct order of size of the given species?

Vedclass Test Series

Exam Paper Generator

Online Exam Module