The equivalent mass of a divalent metal is 31 | vedclass

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(D) The atomic weight of the metal is calculated as: $	ext{Atomic weight} = 	ext{Equivalent mass} 	imes 	ext{Valency}$.Given,$	ext{Equivalent mas

Vedclass · Accepted Answer

$\frac{63.64}{6.023 	imes 10^{23}} \ g$

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(D) The atomic weight of the metal is calculated as: $	ext{Atomic weight} = 	ext{Equivalent mass} 	imes 	ext{Valency}$.Given,$	ext{Equivalent mass} = 31.82$ and the metal is divalent $(n = 2)$.$	ext{Atomic weight} = 31.82 	imes 2 = 63.64 \ g/mol$.To find the mass of a single atom,we divide the molar mass by Avogadro's number $(N_A \approx 6.023 	imes 10^{23} \ mol^{-1})$.$	ext{Mass of single atom} = \frac{63.64}{6.023 	imes 10^{23}} \ g$.

The equivalent mass of a divalent metal is $31.82$. What is the mass of a single atom of this metal?

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