The equivalent resistance between the points $A$ and $B$ in the following circuit is $\frac{x}{5} \Omega$. The value of $x$ is . . . . . . .

  • A
    $15$
  • B
    $21$
  • C
    $10$
  • D
    $25$

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As shown in the figure,a $5\,V$ battery with $2\,\Omega$ internal resistance and a $2\,V$ battery with $1\,\Omega$ internal resistance are connected to a $10\,\Omega$ resistor. The current flowing through the $10\,\Omega$ resistor is:

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The equivalent resistance between $A$ and $B$ in the given circuit is . . . . . . . . (in $\Omega$)

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