The equivalent weight of a divalent metal is $31.82$. The weight of a single atom is

An appropriate method for molecular weight determination of chloroform $(CHCl_3)$ is:

$10 \, g$ of $CaCO_3$ contains

Many elements have non-integral atomic masses because:

$A$ metal $M$ (specific heat $0.16 \ J \ g^{-1} \ K^{-1}$) forms a metal chloride with $65\%$ chlorine present in it. The formula of the metal chloride will be:

Chlorine has two naturally occurring isotopes,${}^{35}Cl$ and ${}^{37}Cl$. If the atomic mass of $Cl$ is $35.45$,the ratio of natural abundance of ${}^{35}Cl$ and ${}^{37}Cl$ is closest to (in $: 1$)