(C) Total expenditure $= 560 + 420 + 180 + 160 + 120 = 1440$.The angle of the sector for clothes is calculated as:$\text{Angle} = \left( \frac{\text{E

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(C) Total expenditure $= 560 + 420 + 180 + 160 + 120 = 1440$.The angle of the sector for clothes is calculated as:$\text{Angle} = \left( \frac{\text{Expenditure on clothes}}{\text{Total expenditure}} \right) \times 360^o$$\text{Angle} = \left( \frac{180}{1440} \right) \times 360^o$$\text{Angle} = \frac{1}{8} \times 360^o = 45^o$.

Class 11 Mathematics Statistics Word problem -Statistics

Difficult

The expenditure of a family for a certain month were as follows:
Food - Rs. $560$,Rent - Rs. $420$,Clothes - Rs. $180$,Education - Rs. $160$,Other items - Rs. $120$
$A$ pie graph representing this data would show the expenditure for clothes by a sector whose angle equals......$^o$

A
$180$
B
$90$
C
$45$
D
$64$

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Word problem -Statistics

In a frequency distribution,if $d_i$ is the deviation of observations from $a$,and the mean is given by $\text{Mean} = a + \frac{\Sigma f_i d_i}{\Sigma f_i}$,then what is $a$?

Medium

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The frequency distribution of daily working expenditure of families in a locality is as follows:

Expenditure in $Rs. (x)$ $0-50$ $50-100$ $100-150$ $150-200$ $200-250$

No. of families $(f)$ $24$ $33$ $37$ $b$ $25$

If the mode of the distribution is $Rs. 140$,then the value of $b$ is:

DifficultAIEEE 2012

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The possible values of $x$ if the standard deviation $(SD)$ of the numbers $2, 3, 2x$,and $11$ is $3.5$ are equal to:

MediumAP EAMCET 2021

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If the mean of two samples of sizes $20$ and $30$ are $25$ and $10$ respectively,and their variances are $9$ and $16$ respectively,then their combined variance is:

MediumAP EAMCET 2020

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If $\bar{x}_1$ and $\bar{x}_2$ are the means of two distributions such that $\bar{x}_1 < \bar{x}_2$ and $\bar{x}$ is the mean of the combined distribution,then

Medium

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Expenditure in $Rs. (x)$	$0-50$	$50-100$	$100-150$	$150-200$	$200-250$
No. of families $(f)$	$24$	$33$	$37$	$b$	$25$

The expenditure of a family for a certain month were as follows:Food - Rs. $560$,Rent - Rs. $420$,Clothes - Rs. $180$,Education - Rs. $160$,Other items - Rs. $120$$A$ pie graph representing this data would show the expenditure for clothes by a sector whose angle equals......$^o$

Similar Questions

In a frequency distribution,if $d_i$ is the deviation of observations from $a$,and the mean is given by $\text{Mean} = a + \frac{\Sigma f_i d_i}{\Sigma f_i}$,then what is $a$?

The frequency distribution of daily working expenditure of families in a locality is as follows: Expenditure in $Rs. (x)$ $0-50$ $50-100$ $100-150$ $150-200$ $200-250$ No. of families $(f)$ $24$ $33$ $37$ $b$ $25$ If the mode of the distribution is $Rs. 140$,then the value of $b$ is:

The possible values of $x$ if the standard deviation $(SD)$ of the numbers $2, 3, 2x$,and $11$ is $3.5$ are equal to:

If the mean of two samples of sizes $20$ and $30$ are $25$ and $10$ respectively,and their variances are $9$ and $16$ respectively,then their combined variance is:

If $\bar{x}_1$ and $\bar{x}_2$ are the means of two distributions such that $\bar{x}_1 < \bar{x}_2$ and $\bar{x}$ is the mean of the combined distribution,then

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The expenditure of a family for a certain month were as follows:
Food - Rs. $560$,Rent - Rs. $420$,Clothes - Rs. $180$,Education - Rs. $160$,Other items - Rs. $120$
$A$ pie graph representing this data would show the expenditure for clothes by a sector whose angle equals......$^o$

The frequency distribution of daily working expenditure of families in a locality is as follows:

Expenditure in $Rs. (x)$ $0-50$ $50-100$ $100-150$ $150-200$ $200-250$

No. of families $(f)$ $24$ $33$ $37$ $b$ $25$

If the mode of the distribution is $Rs. 140$,then the value of $b$ is: