The extra stability of half-filled subshells | vedclass

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(B) The extra stability of half-filled subshells is attributed to the following factors:$(I)$ Symmetrical distribution of electrons: Electrons are dis

Vedclass · Accepted Answer

$(A), (B), (D)$ and $(E)$ only

Vedclass · Answer

(B) The extra stability of half-filled subshells is attributed to the following factors:$(I)$ Symmetrical distribution of electrons: Electrons are distributed symmetrically in the orbitals,which leads to lower energy.$(II)$ Larger exchange energy: The number of possible exchanges for electrons with parallel spins is maximum in half-filled and fully-filled configurations,resulting in higher exchange energy and greater stability.$(III)$ Smaller coulombic repulsion: Due to the symmetrical arrangement,the inter-electronic repulsion is minimized.$(IV)$ Smaller shielding of electrons by one another: The effective nuclear charge experienced by the electrons is optimized in these configurations.Therefore,statements $(A), (B), (D),$ and $(E)$ are correct.

Similar Questions

Arrange the following in the increasing order of their energy:
$(i)$ $n = 2, l = 0, m_l = 0, m_s = +\frac{1}{2}$
$(ii)$ $n = 2, l = 1, m_l = +1, m_s = -\frac{1}{2}$
$(iii)$ $n = 3, l = 2, m_l = +1, m_s = -\frac{1}{2}$
$(iv)$ $n = 3, l = 1, m_l = -1, m_s = +\frac{1}{2}$

Statement $A$: In a potassium atom,the $19^{th}$ electron enters the $4s$-orbital instead of the $3d$-orbital.
Reason $R$: The $(n + l)$ rule is followed to determine the minimum energy of an orbital.

The correct order of energy of $2s$-orbitals in $H$,$Li$,$Na$ and $K$ is:

The maximum number of electrons present in an orbit with azimuthal quantum number $l = 3$ is:

How many orbitals are present in a $g$ subshell?

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