The factor not needed to calculate heat lost or gained when there is no change of state is

  • A
    Weight
  • B
    Specific heat
  • C
    Relative density
  • D
    Temperature change

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Water of mass $5 \ kg$ in a closed vessel is at a temperature of $20^{\circ} C$. If the temperature of the water when heated for a time of $10 \ minutes$ becomes $30^{\circ} C$, then the increase in the internal energy of the water is (Specific heat capacity of water $= 4200 \ J \ kg^{-1} \ K^{-1}$) (in $kJ$)

Derive the equation for the molar specific heat capacity of solids.

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