The figure below shows currents in a part of | vedclass

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(A) According to Kirchhoff's first law (junction rule),the sum of currents entering a junction equals the sum of currents leaving it.$1$. At junction

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$1.7$

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(A) According to Kirchhoff's first law (junction rule),the sum of currents entering a junction equals the sum of currents leaving it.$1$. At junction $A$,two currents of $2\,A$ each enter. Therefore,the current leaving junction $A$ towards junction $B$ is $i_{AB} = 2\,A + 2\,A = 4\,A$.$2$. At junction $B$,a current of $4\,A$ enters from $A$,and a current of $1\,A$ leaves. Therefore,the current leaving junction $B$ towards junction $C$ is $i_{BC} = 4\,A - 1\,A = 3\,A$.$3$. At junction $C$,a current of $3\,A$ enters from $B$,and a current of $1.3\,A$ leaves. The remaining current $i$ also leaves junction $C$. Therefore,$3\,A = 1.3\,A + i$,which gives $i = 3\,A - 1.3\,A = 1.7\,A$.

The figure below shows currents in a part of an electric circuit. The current $i$ is ............. $A$.

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