The figure given below shows three velocity-s | vedclass

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(A) In the given graph,curve $a$ represents the normal enzyme reaction with the highest $V_{max}$.Curve $b$ shows competitive inhibition,where the $K_

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$a -$ normal enzyme reaction,$b -$ competitive inhibition,$c -$ non-competitive inhibition

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(A) In the given graph,curve $a$ represents the normal enzyme reaction with the highest $V_{max}$.Curve $b$ shows competitive inhibition,where the $K_m$ increases but the $V_{max}$ remains the same as the normal reaction because the inhibition can be overcome by increasing the substrate concentration.Curve $c$ shows non-competitive inhibition,where the $V_{max}$ is decreased because the inhibitor binds to a site other than the active site,reducing the enzyme's efficiency regardless of substrate concentration.

Column-$I$	Column-$II$
$1$. Oleate	$a$. Triose sugar
$2$. Trihydroxy alcohol	$b$. Unsaturated fatty acid
$3$. Glyceraldehyde	$c$. Subcutaneous fat layer
$4$. Amylopectin	$d$. Glycerol
$5$. Ergosterol	$e$. Branched chain of glucose units

The figure given below shows three velocity-substrate concentration curves for an enzyme reaction. What do the curves $a, b$ and $c$ depict respectively?

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$1$. Oleate $a$. Triose sugar

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