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(B) For a wave travelling in the negative $x$-direction, the velocity of a particle at any point is given by $v_p = -v \cdot (	ext{slope})$.Here, $v$

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$d, e, f$

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(B) For a wave travelling in the negative $x$-direction, the velocity of a particle at any point is given by $v_p = -v \cdot (	ext{slope})$.Here, $v$ is the wave speed (positive value) and the slope is $\frac{dy}{dx}$ at that point.For the particle to move in the negative $y$-direction, $v_p$ must be negative.This implies that $-v \cdot (	ext{slope}) Looking at the graph, the slope is positive in the regions where the curve is increasing (going upwards from left to right).These regions correspond to the points $d, e, f$.Thus, the points $d, e, f$ are moving in the negative $y$-direction.

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