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(C) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction must equal the sum of currents leaving the junction.Let us an

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$13$

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(C) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction must equal the sum of currents leaving the junction.Let us analyze the junctions in the circuit.At the left junction,a current of $10 \, A$ enters,and a current of $6 \, A$ leaves downwards. Therefore,the current flowing upwards towards the top junction is $10 \, A - 6 \, A = 4 \, A$.At the top junction,a current of $1 \, A$ enters from the top and $4 \, A$ enters from the left branch. Thus,the total current leaving the top junction towards the right junction is $1 \, A + 4 \, A = 5 \, A$.At the bottom junction,a current of $6 \, A$ enters from the left and $2 \, A$ enters from the bottom. Thus,the total current leaving the bottom junction towards the right junction is $6 \, A + 2 \, A = 8 \, A$.Finally,at the right junction,the current $I$ is the sum of the currents arriving from the top junction $(5 \, A)$ and the bottom junction $(8 \, A)$.Therefore,$I = 5 \, A + 8 \, A = 13 \, A$.

The figure shows a network of currents. The magnitude of currents is shown in the figure. The current $I$ will be ........... $A$.

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