The figure shows an apparatus suggested by Fa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The motional electromotive force $(EMF)$ induced in the river water moving with velocity $u$ through the vertical magnetic field $B_v$ across a di

Vedclass · Accepted Answer

$\frac{B_v ud}{R + \frac{\rho d}{ab}}$

Vedclass · Answer

(B) The motional electromotive force $(EMF)$ induced in the river water moving with velocity $u$ through the vertical magnetic field $B_v$ across a distance $d$ is given by $\varepsilon = B_v ud$.The resistance of the river water between the two plates can be calculated using the formula $R_w = ho \frac{L}{A}$,where $L = d$ (distance between plates) and $A = a 	imes b$ (area of the plates). Thus,$R_w = \frac{ho d}{ab}$.The total resistance in the circuit is the sum of the load resistance $R$ and the internal resistance of the water $R_w$,so $R_{eq} = R + \frac{ho d}{ab}$.Using Ohm's law,the current $I$ through the load resistance $R$ is $I = \frac{\varepsilon}{R_{eq}} = \frac{B_v ud}{R + \frac{ho d}{ab}}$.

Similar Questions

$A$ copper disc of radius $0.1 \ m$ rotates about its centre with $10$ revolutions per second in a uniform magnetic field of $0.1 \ T$. The emf induced across the radius of the disc is

$A$ long metal rod of length $L$ completes the circuit as shown. The area of the circuit is perpendicular to the magnetic field $B$. The total resistance of the circuit is $R$. The force needed to move the rod in the direction as shown with a constant speed $V$ is:

$A$ coil has $1000$ turns and $500 \text{ cm}^2$ as its area. The plane of the coil is placed at right angles to a magnetic induction field of $2 \times 10^{-5} \text{ Wb/m}^2$. The coil is rotated through $180^{\circ}$ in $0.2 \text{ s}$. The average emf induced in the coil,in $\text{mV}$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module