The figure shows currents in a part of an ele | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Kirchhoff's current law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$,the inc

Vedclass · Accepted Answer

$3.5$

Vedclass · Answer

(A) According to Kirchhoff's current law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$,the incoming currents are $1 \ A$ and $4 \ A$. Therefore,the current leaving junction $A$ towards junction $B$ is $I_{AB} = 1 \ A + 4 \ A = 5 \ A$.At junction $B$,the incoming current is $I_{AB} = 5 \ A$. The outgoing currents are $0.5 \ A$ and the current towards junction $C$ $(I_{BC})$. Thus,$5 \ A = 0.5 \ A + I_{BC}$,which gives $I_{BC} = 4.5 \ A$.At junction $C$,the incoming current is $I_{BC} = 4.5 \ A$. The outgoing currents are $I$ and $1 \ A$. Thus,$4.5 \ A = I + 1 \ A$,which gives $I = 3.5 \ A$.

The figure shows currents in a part of an electric circuit. Then the current $I$ is: (in $A$)

Similar Questions

If the internal resistance of the battery is $1\, \Omega$, then what is the reading of the ammeter?

The galvanometer has no deflection and the length of wire $AB$ is $350 \, cm$. Then $AC$ equals to ............... $cm$.

The equivalent resistance between $P$ and $Q$ in the given figure is ............... $\Omega$.

The readings of ammeters $A_1, A_2$ and $A_3$ will be respectively:

In the circuit diagram shown below,the magnitude and direction of the flow of current respectively would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module