The final product C in the following series o | vedclass

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Question

(A) $1$. Reduction: Nitrobenzene $(C_6H_5NO_2)$ reacts with $Sn/HCl$ to form aniline $(C_6H_5NH_2)$,which is product $A$.$2$. Diazotization: Aniline r

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$1-$(phenylazo)naphthalen$-2-$ol

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(A) $1$. Reduction: Nitrobenzene $(C_6H_5NO_2)$ reacts with $Sn/HCl$ to form aniline $(C_6H_5NH_2)$,which is product $A$.$2$. Diazotization: Aniline reacts with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ to form benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$,which is product $B$.$3$. Coupling Reaction: Benzene diazonium chloride reacts with $\beta$-naphthol in the presence of $NaOH$ to form an azo dye. The coupling occurs at the ortho position relative to the $-OH$ group in $\beta$-naphthol,yielding $1-$(phenylazo)naphthalen$-2-$ol as the final product $C$.

The final product $C$ in the following series of reactions is:

Similar Questions

The correct order of basicities of the following compounds is:
$1. CH_3-C(=NH)NH_2$ (Acetamidine)
$2. (CH_3)_2NH$ (Dimethylamine)
$3. CH_3-CH_2-NH_2$ (Ethylamine)
$4. CH_3-CONH_2$ (Acetamide)

The major product in the following reaction is:

Identify $B$ formed in the reaction: $Cl-(CH_2)_4-Cl$ $\xrightarrow{\text{excess } NH_3} A$ $\xrightarrow{NaOH} B + H_2O + NaCl$

Arrange the following in the order of decreasing basicity:
$I. RN=CHR^1$ $II. RC \equiv N$ $III. RNH_2$

The correct order of basic strength for the given compounds is:

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