The final product A, formed in the following | vedclass

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(B) $1$. Bromobenzene reacts with $Mg$ in ether to form phenylmagnesium bromide $(C_6H_5MgBr)$.$2$. Phenylmagnesium bromide reacts with $CO_2$ followe

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Aniline

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(B) $1$. Bromobenzene reacts with $Mg$ in ether to form phenylmagnesium bromide $(C_6H_5MgBr)$.$2$. Phenylmagnesium bromide reacts with $CO_2$ followed by acid hydrolysis $(H^+)$ to yield benzoic acid $(C_6H_5COOH)$.$3$. Benzoic acid reacts with $NH_3$ and heat $(\Delta)$ to form benzamide $(C_6H_5CONH_2)$.$4$. Benzamide undergoes the Hoffmann bromamide degradation reaction with $Br_2$ and $NaOH$ to form aniline $(C_6H_5NH_2)$.Therefore, the final product $A$ is aniline.

The final product $A$, formed in the following multistep reaction sequence is:

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