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(B) $1$. Nitrobenzene reacts with $Br_2/FeBr_3$ to form $m$-bromonitrobenzene $(P)$ because the $-NO_2$ group is meta-directing.$2$. $m$-Bromonitroben

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$3-$Bromophenol

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(B) $1$. Nitrobenzene reacts with $Br_2/FeBr_3$ to form $m$-bromonitrobenzene $(P)$ because the $-NO_2$ group is meta-directing.$2$. $m$-Bromonitrobenzene $(P)$ is reduced by $Sn/conc. HCl$ to form $m$-bromoaniline $(Q)$.$3$. $m$-Bromoaniline $(Q)$ reacts with $NaNO_2/dil. HCl$ at $273 \ K$ to form $m$-bromobenzenediazonium chloride.$4$. Finally,warming with water replaces the diazonium group with an $-OH$ group to form $m$-bromophenol $(R)$.

The final product $R$ for the reaction is:

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