The first ionisation energies of alkaline ear | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The first ionisation energy is the energy required to remove the most loosely bound electron from an isolated gaseous atom. As we move from alkali

Vedclass · Accepted Answer

There is increase in the nuclear charge of the alkaline earth metals

Vedclass · Answer

(A) The first ionisation energy is the energy required to remove the most loosely bound electron from an isolated gaseous atom. As we move from alkali metals (Group $1$) to alkaline earth metals (Group $2$) in the same period,the nuclear charge increases. An increase in nuclear charge leads to a stronger electrostatic attraction between the nucleus and the valence electrons. Consequently,more energy is required to remove an electron from alkaline earth metals compared to alkali metals. Therefore,the first ionisation energies of alkaline earth metals are higher due to the increase in nuclear charge.

Atomic number	$I_1$ $(kJ/mol)$	$I_2$ $(kJ/mol)$	$I_3$ $(kJ/mol)$
$n$	$I_1$	$I_2$	$I_3$
$n+1$	$1681$	$3374$	$6050$
$n+2$	$2081$	$3952$	$6122$
$n+3$	$496$	$4562$	$6910$
$n+4$	$738$	$1451$	$7733$

The first ionisation energies of alkaline earth metals are higher than those of the alkali metals. This is because

Similar Questions

The second ionization potential of $Li$,$Be$,and $B$ is in the order:

Consider the elements $Ne$,$Na$,and $Mg$. The element with the highest first ionization enthalpy and the element with the lowest second ionization enthalpy,respectively,are:

Which of the following has the highest first ionization energy?

Find the highest ratio of $IP$ values of the given pair of elements.

Vedclass Test Series

Exam Paper Generator

Online Exam Module