(A) Given: First term $a = 2$,common difference $d = 4$,and number of terms $n = 40$.The formula for the sum of $n$ terms of an $A.P.$ is $S_n = \frac

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(A) Given: First term $a = 2$,common difference $d = 4$,and number of terms $n = 40$.The formula for the sum of $n$ terms of an $A.P.$ is $S_n = \frac{n}{2}[2a + (n - 1)d]$.Substituting the values:$S_{40} = \frac{40}{2}[2(2) + (40 - 1)4]$$S_{40} = 20[4 + 39 \times 4]$$S_{40} = 20[4 + 156]$$S_{40} = 20 \times 160 = 3200$.