The Fischer projection formula of L-(-)-gluco | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $D$ and $L$ configuration of monosaccharides is determined by the position of the $-OH$ group on the chiral carbon furthest from the carbonyl

Vedclass · Accepted Answer

Vedclass · Answer

(D) The $D$ and $L$ configuration of monosaccharides is determined by the position of the $-OH$ group on the chiral carbon furthest from the carbonyl group (the $C-5$ carbon in glucose). However,the question asks for the enantiomer of $D-(+)-glucose$,which is $L-(-)-glucose$. In $D-(+)-glucose$,the $-OH$ groups are at positions: $C-2$ (right),$C-3$ (left),$C-4$ (right),and $C-5$ (right). In $L-(-)-glucose$,the configuration at every chiral center is inverted compared to $D-glucose$. Therefore,in $L-(-)-glucose$,the $-OH$ groups are at positions: $C-2$ (left),$C-3$ (right),$C-4$ (left),and $C-5$ (left). This corresponds to the structure shown in option $D$.

The Fischer projection formula of $L-(-)-glucose$ is:

Similar Questions

Which of the following contains a dextrorotatory sugar?

Identify the correct set of monosaccharides present in sucrose $(X)$,lactose $(Y)$ and maltose $(Z)$.

$\alpha-D-(+)$-glucose and $\beta-D-(+)$-glucose are

Which of the following is a trisaccharide?

Vedclass Test Series

Exam Paper Generator

Online Exam Module