The following graph illustrates:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The graph shows a linear relationship between volume $(V)$ and temperature in degrees Celsius $(t)$.According to Charles's Law,the volume of a fix

Vedclass · Accepted Answer

Charles's law

Vedclass · Answer

(B) The graph shows a linear relationship between volume $(V)$ and temperature in degrees Celsius $(t)$.According to Charles's Law,the volume of a fixed mass of gas is directly proportional to its absolute temperature ($T$ in Kelvin).The relationship is given by: $V_t = V_0(1 + \frac{t}{273.15})$This can be rewritten as: $V_t = V_0 + (\frac{V_0}{273.15})t$Comparing this with the linear equation $Y = mx + C$,where $Y = V_t$,$x = t$,$m = \frac{V_0}{273.15}$,and $C = V_0$.This linear plot of $V$ versus $t$ $(^{\circ}C)$ is characteristic of Charles's Law.Therefore,the correct option is $(B)$.

Similar Questions

At what temperature will the volume of a gas be halved if the initial temperature is $17^{\circ}C$ and the pressure remains constant (in $^{\circ}C$)?

The compressibility factor for an ideal gas is

At what temperature $K$ will the kinetic energy of $0.3 \ mol$ of $He$ be equal to the kinetic energy of $0.4 \ mol$ of $Ar$ at $400 \ K$?

If a gas occupies a volume of $1.5 \, L$ at a pressure of $75 \, cm \, Hg$,then at the same temperature,the volume of the gas at a pressure of $50 \, cm \, Hg$ will be ........... $L$. (in $.25$)

If the density of gas $A$ is $1.5$ times that of gas $B$,and the molecular mass of $A$ is $M$,then the molecular mass of $B$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module