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(B) From the given potential energy diagram: $1$. The energy of the reactant $(A)$ is $E_{A} = 10 \ kJ \ mol^{-1}$. $2$. The energy of the product $(P

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$15, 5$

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(B) From the given potential energy diagram: $1$. The energy of the reactant $(A)$ is $E_{A} = 10 \ kJ \ mol^{-1}$. $2$. The energy of the product $(P)$ is $E_{P} = 5 \ kJ \ mol^{-1}$. $3$. The threshold energy (peak of the curve) is $E_{threshold} = 25 \ kJ \ mol^{-1}$. $4$. The activation energy $(E_{a})$ is calculated as $E_{threshold} - E_{A} = 25 - 10 = 15 \ kJ \ mol^{-1}$. $5$. The heat of reaction $(\Delta H)$ is calculated as $E_{P} - E_{A} = 5 - 10 = -5 \ kJ \ mol^{-1}$. $6$. The magnitude of the heat of reaction is $|\Delta H| = |-5| = 5 \ kJ \ mol^{-1}$. Therefore,the activation energy is $15 \ kJ \ mol^{-1}$ and the heat of reaction is $5 \ kJ \ mol^{-1}$.

The following graph is obtained for a reaction $(A \rightarrow P)$. The activation energy ($E_{a}$ in $kJ \ mol^{-1}$) and heat of reaction ($|\Delta H|$ in $kJ \ mol^{-1}$) for this reaction are respectively ($x=$ reaction coordinate; $y=E$ in $kJ \ mol^{-1}$)

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