The following graph is obtained for an ideal | vedclass

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(B) According to Raoult's Law for a solution containing a non-volatile solute,the vapour pressure of the solution $(P_{sol})$ is directly proportional

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mole fraction of solvent,vapour pressure of solution.

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(B) According to Raoult's Law for a solution containing a non-volatile solute,the vapour pressure of the solution $(P_{sol})$ is directly proportional to the mole fraction of the solvent $(x_{solvent})$: $P_{sol} = P^0_{solvent} 	imes x_{solvent}$ Since $x_{solvent} + x_{solute} = 1$,we can write: $P_{sol} = P^0_{solvent} 	imes (1 - x_{solute}) = P^0_{solvent} - P^0_{solvent} 	imes x_{solute}$ This represents a linear equation $y = mx + c$ where the slope is negative. However,if the graph shows a direct linear increase starting from the origin,it represents the relationship between the vapour pressure of the solution and the mole fraction of the solvent $(P_{sol} \propto x_{solvent})$. Thus,the $x$-axis represents the mole fraction of the solvent and the $y$-axis represents the vapour pressure of the solution.

The following graph is obtained for an ideal solution containing a non-volatile solute. The $x$- and $y$-axes represent,respectively:

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