Which of the following square-planar complexe | vedclass

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(C) For a square-planar complex to exhibit $cis-trans$ isomerism,it must have the general formula $[MA_2B_2]$ or $[MA_2BC]$.$1$. $[PtCl_4]^{2-}$ is of

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$[PtCl_2(CN)_2]^{2-}$

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(C) For a square-planar complex to exhibit $cis-trans$ isomerism,it must have the general formula $[MA_2B_2]$ or $[MA_2BC]$.$1$. $[PtCl_4]^{2-}$ is of the type $[MA_4]$,which does not show isomerism.$2$. $[PtCl_3(NH_3)]^-$ is of the type $[MA_3B]$,which does not show isomerism.$3$. $[PtCl_2(CN)_2]^{2-}$ is of the type $[MA_2B_2]$,where $M = Pt$,$A = Cl^-$,and $B = CN^-$. This complex can exist in $cis$ and $trans$ forms.$4$. $[PtCl_2(en)]$ is of the type $[MA_2(AA)]$,where $en$ is a bidentate ligand. Since the bidentate ligand occupies adjacent positions,it cannot form a $trans$ isomer.

Which of the following square-planar complexes exhibits $cis-trans$ isomerism?

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