The following table gives the life times of $400$ neon lamps:
The time (in hours) Number of lamps $300-400$ $14$ $400-500$ $56$ $500-600$ $60$ $600-700$ $86$ $700-800$ $74$ $800-900$ $62$ $900-1000$ $48$
$(i)$ Represent the given information with the help of a histogram.
$(ii)$ How many lamps have a life time of more than $700$ hours?
| The time (in hours) | Number of lamps |
| $300-400$ | $14$ |
| $400-500$ | $56$ |
| $500-600$ | $60$ |
| $600-700$ | $86$ |
| $700-800$ | $74$ |
| $800-900$ | $62$ |
| $900-1000$ | $48$ |
$(i)$ Represent the given information with the help of a histogram.
$(ii)$ How many lamps have a life time of more than $700$ hours?
(N/A) $(i)$ By taking the life time (in hours) of neon lamps on the $x$-axis and the number of lamps on the $y$-axis,the histogram of the given information can be drawn as shown in the figure.
Here,$1$ unit on the $y$-axis represents $10$ lamps.
$(ii)$ The number of neon lamps having a lifetime of more than $700$ hours is the sum of the number of lamps in the intervals $700-800$,$800-900$,and $900-1000$.
Therefore,the number of neon lamps having a lifetime of more than $700$ hours is $74 + 62 + 48 = 184$.
Here,$1$ unit on the $y$-axis represents $10$ lamps.
$(ii)$ The number of neon lamps having a lifetime of more than $700$ hours is the sum of the number of lamps in the intervals $700-800$,$800-900$,and $900-1000$.
Therefore,the number of neon lamps having a lifetime of more than $700$ hours is $74 + 62 + 48 = 184$.
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$A$ survey conducted by an organisation for the cause of illness and death among women between the ages $15-44$ (in years) worldwide,found the following figures (in $\%$):
$S$.No Causes Female fatality rate $(\%)$ $1.$ Reproductive health conditions $31.8$ $2.$ Neuropsychiatric conditions $25.4$ $3.$ Injuries $12.4$ $4.$ Cardiovascular conditions $4.3$ $5.$ Respiratory conditions $4.1$ $6.$ Other causes $22.0$
$(i)$ Represent the information given above graphically.
$(ii)$ Which condition is the major cause of women's ill health and death worldwide?
$(iii)$ Try to find out,with the help of your teacher,any two factors which play a major role in the cause in $(ii)$ above being the major cause.
| $S$.No | Causes | Female fatality rate $(\%)$ |
| $1.$ | Reproductive health conditions | $31.8$ |
| $2.$ | Neuropsychiatric conditions | $25.4$ |
| $3.$ | Injuries | $12.4$ |
| $4.$ | Cardiovascular conditions | $4.3$ |
| $5.$ | Respiratory conditions | $4.1$ |
| $6.$ | Other causes | $22.0$ |
$(i)$ Represent the information given above graphically.
$(ii)$ Which condition is the major cause of women's ill health and death worldwide?
$(iii)$ Try to find out,with the help of your teacher,any two factors which play a major role in the cause in $(ii)$ above being the major cause.
Medium
View SolutionConsider the marks,out of $100$,obtained by $51$ students of a class in a test,given in the table below. Draw a frequency polygon corresponding to this frequency distribution table.
Marks Number of students $0-10$ $5$ $10-20$ $10$ $20-30$ $4$ $30-40$ $6$ $40-50$ $7$ $50-60$ $3$ $60-70$ $2$ $70-80$ $2$ $80-90$ $3$ $90-100$ $9$ Total $51$
| Marks | Number of students |
| $0-10$ | $5$ |
| $10-20$ | $10$ |
| $20-30$ | $4$ |
| $30-40$ | $6$ |
| $40-50$ | $7$ |
| $50-60$ | $3$ |
| $60-70$ | $2$ |
| $70-80$ | $2$ |
| $80-90$ | $3$ |
| $90-100$ | $9$ |
| Total | $51$ |
Medium
View SolutionThe relative humidity (in $\%$) of a certain city for a month of $30$ days was as follows:
$98.1$ $98.6$ $99.2$ $90.3$ $86.5$ $95.3$ $92.9$ $96.3$ $94.2$ $95.1$ $89.2$ $92.3$ $97.1$ $93.5$ $92.7$ $95.1$ $97.2$ $93.3$ $95.2$ $97.3$ $96.2$ $92.1$ $84.9$ $90.2$ $95.7$ $98.3$ $97.3$ $96.1$ $92.1$ $89$
$(i)$ Construct a grouped frequency distribution table with classes $84-86, 86-88$,etc.
$(ii)$ Which month or season do you think this data is about?
$(iii)$ What is the range of this data?
| $98.1$ | $98.6$ | $99.2$ | $90.3$ | $86.5$ | $95.3$ | $92.9$ | $96.3$ | $94.2$ | $95.1$ |
| $89.2$ | $92.3$ | $97.1$ | $93.5$ | $92.7$ | $95.1$ | $97.2$ | $93.3$ | $95.2$ | $97.3$ |
| $96.2$ | $92.1$ | $84.9$ | $90.2$ | $95.7$ | $98.3$ | $97.3$ | $96.1$ | $92.1$ | $89$ |
$(i)$ Construct a grouped frequency distribution table with classes $84-86, 86-88$,etc.
$(ii)$ Which month or season do you think this data is about?
$(iii)$ What is the range of this data?
Medium
View SolutionThe following observations have been arranged in ascending order. If the median of the data is $63$,find the value of $x.$
$29, 32, 48, 50, x, x+ 2, 72, 78, 84, 95$
$29, 32, 48, 50, x, x+ 2, 72, 78, 84, 95$
Easy
View Solution$A$ family with a monthly income of $20,000$ had planned the following expenditures per month under various heads:
Heads Expenditure (in thousand rupees) Grocery $4$ Rent $5$ Education of children $5$ Medicine $2$ Fuel $2$ Entertainment $1$ Miscellaneous $1$
Draw a bar graph for the data above.
| Heads | Expenditure (in thousand rupees) |
|---|---|
| Grocery | $4$ |
| Rent | $5$ |
| Education of children | $5$ |
| Medicine | $2$ |
| Fuel | $2$ |
| Entertainment | $1$ |
| Miscellaneous | $1$ |
Draw a bar graph for the data above.
Medium
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